[C++] 纯文本查看 复制代码
#include <stdio.h>
#define M sizeof(unsigned int)*9
/*将无符号整数 n 转换成 d (2<= d <=16)进制所表示的字符串 s */
int translation(unsigned n, int d, char s[])
{
static char digits[] = "0123456789abcdefghijklmnopqrstuvwxyz"; /* 总共36进制 */
char buf[M+1];
int j, i = M;
if( d < 2 || d > 36) {
s[0] = '\0'; /* 不合理进制数, 使 s 为空字符串*/
return 0; /* 不合理进制数, 函数返回 0 */
}
buf[i] = '\0';
do {
buf[--i] = digits[n%d]; /*得出最低位,将对应字符填入对应数组中*/
n /= d;
}while(n);
for (j = 0; (s[j] = buf[i]) != 0; j++, i++); /*拷贝结果*/
return j;
}
int main()
{
unsigned int num = 0;
int scale[] = {2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,1};
char str[64];
int i;
printf ("Input a number to ranslate:");
scanf("%d", &num);
printf ("You input is %d\n", num);
printf ("The translation result are:\n");
for (i = 0; i < sizeof(scale)/sizeof(scale[0]); i++) {
if(translation(num, scale[i], str))
printf("%5d = %s(%d)\n", num, str, scale[i]);
else
printf("%5d => (%d) Error! \n", num, scale[i]);
}
return 0;
}