字符串替换

beyes

假设有一个字符串，需要将里面包含 sim1 替换为 sim 。

这个事情如果用正则表达式来处理，那极为简单。下面使用 C 语言来实现，代码如下：

[C++] 纯文本查看 复制代码

#include <stdio.h>
#include <string.h>

int main()
{
    char str[] = "abcdefsimokaeikjfasim1ekdicakdlasimldaisim1eeazkadslsimlaisime1azsdfa";

    char *p;
    char *p1;

    int i = 0;
    int len = strlen(str);
    int tmplen;

    char tmp[len + 1];
    char tmp2[len + 1];

    memset(tmp, '\0', len+1);
    memset(tmp2, '\0', len+1);
    
    strcpy(tmp2, str);
    
    while ((p1 = strstr(tmp2, "sim1"))) {
        p = tmp2;
        while (p != (p1 + 3)) {
            tmp[i] = *p;
            p++;
            i++;
        }
        p1 += 4;
        tmplen = strlen(p1);
        memmove(tmp2, p1, tmplen);
        p1 = tmp2;
        p1 += tmplen;
        memset(p1, '\0', len+1-tmplen);
    }
    p = tmp;
    p += i;
    strcat(p, tmp2);
    
    printf ("%s\n", str);
    printf ("%s\n", tmp);
    return 0;

}

运行输出：

[beyes@beyes   c]$ ./dele
abcdefsimokaeikjfasim1ekdicakdlasimldaisim1eeazkadslsimlaisime1azsdfa
abcdefsimokaeikjfasimekdicakdlasimldaisimeeazkadslsimlaisime1azsdfa