输出下一秒时间

beyes

编写一个函数，要求输入年月日时分秒，输出该年月日时分秒的下一秒。如输入2004年12月31日23时59分59秒，则输出2005年1月1日0时0分0秒。

#include <stdio.h> #include <stdlib.h> void next_second(int *year, int *month, int *day, int *hour, int *min, int *second); int main() {     int year, month, day, hour, min, second;     printf("input year: ");     scanf("%d", &year);     printf("\n");     printf("input month: ");     scanf("%d", &month);     printf("\n");     printf("input day: ");     scanf("%d", &day);     printf("\n");     printf("input hour: ");     scanf("%d", &hour);     printf("\n");     printf("input min: ");     scanf("%d", &min);     printf("\n");     printf("input second: ");     scanf("%d", &second);     printf("\n");         next_second(&year, &month, &day, &hour, &min, &second);     } void next_second(int *year, int *month, int *day, int *hour, int *min, int *second) {     int leap = 0;         if ((*year % 4 == 0 && *year % 100 != 0) || *year % 400 == 0)         leap = 1;         if ( *year < 1900 || *year > 2099 ) {         printf("请输入在 1900 年与2099 年之间的年数!\n");         exit(1);     }     if( (*second < 0 || *second > 59) || (*min < 0 || *min > 59) || (*hour < 0 || *hour > 23) || (*day < 0 || *day > 31) || (*month < 0 || *month > 12)){         printf("输入时间错误!\n");         exit(1);     }     if( *month == 2 || *month == 4 || *month == 6 || *month == 9 || *month == 11) {         if( *day > 30 ) {             printf("对应月份没有 31 天!\n");             exit(1);         }     }     if ( *month == 2 && *day > 28) {         if (!leap ) {             printf("非闰年2月最大天数为28天!\n");             exit(1);         }     }                              if (*second != 59) {         printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, *month, *day, *hour, *min, *second+1);         exit(0);     }     if (*min != 59) {            printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, *month, *day, *hour, *min+1, 0);         exit(0);     }     if (*hour != 23) {         printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, *month, *day, *hour+1, 0, 0);         exit(0);     }     if (*day < 28) {         printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, *month, *day+1, 0, 0, 0);         exit(0);     }     if (*day == 28 && *month == 2 && leap == 0) {         printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, 3, 1, 0, 0, 0);         exit(0);      }     if (*day == 29 && *month == 2) {         printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, 3, 1, 0, 0, 0);         exit(0);     }     if (*day == 31 && *month == 12) {         printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year+1, 1, 1, 0, 0, 0);         exit(0);     } else if (*day == 31 && *month != 12) {         printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, *month+1, 1, 0, 0, 0);         exit(0);     } else {                    printf("下一秒时间为:%d年%d月%d日%d时%d分%d秒\n", *year, *month+1, 1, 0, 0, 0);         exit(0);     }              }